A mixture is having 5 components A, B, C, D and E of size 2, 4, 6, 8 and 10 µm. This mixture is applied to a column having beads of size, 2, 4, 6, and 8 µm. After this, mobile phase is applied. The value of Partition coefficients (Kd) of sample components in stationary and mobile phase will be in the ratio: a) E>D>C>B>A b) A>B>C>D>E c) D>C>B>A>E d) A>D>B>C>E

Correct Answer is b.

Explanation:

 

Distribution coefficient = (concentration of component in stationary phase)/ (concentration of component in mobile phase).

It is represented by Kd (also called as partition coefficient).

E, will travel through the intercellular spaces of the gel, and will not be able to enter the gel. Kd =0; because it has 0 concentration in stationary phase.

On the contrary, “A” will travel through almost all the beads of the gel; therefore, it will be eluted out at the last. Kd = 1; because its concentration in stationary phase is highest.

Kd of B, C, and D will be in between 0 and 1. Kd of B, will be higher than C, because its concentration in gel will be higher than C and D. Same is the case for C and D.